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    Integrate x^3/sqrt((x^2+16)) dx using trig substitution? - Socratic

    WEBJan 28, 2018 · Explanation: Try x = 4tanθ. Then x = 4sec2θdθ. intx^3/sqrt (x^2+16)dx=1/3 (sqrt (16+x^2)/x)^3-sqrt (16+x^2)/x+c Let x=4tanu, then dx=4sec^2udu also secu=sqrt (1+x^2/16)=sqrt (16+x^2)/x and I=intx^3/sqrt (x^2+16)dx = int (64tan^3x)/sqrt (16tan^2u+16)xx4sec^2udu = int (64tan^3x)/ (4secu)xx4sec^2udu = int64tan^3usecudu …

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    Cymath | Math Problem Solver with Steps | Math Solving App

    WEBJoin millions of users in problem solving! +. > <

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    How do you solve (x^2 - 16)(x - 3)^2 + 9x^2 = 0? - Socratic

    WEBSep 5, 2015 · If #abs(x) >= 4# then #(x^2-16) >= 0#, #(x-3)^2 > 0# and #9x^2 > 0#, so #f(x) > 0#. So the only Real roots of #f(x) = 0# are in the range #-4 < x < 4# . The rational root theorem tells us that any rational roots of #f(x) = 0# must be of the form #p/q# in lowest terms, where #p, q in ZZ# , #q > 0# , #p# is a divisor of the constant term #144# and #q# …

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    How do you integrate #int x^3 sqrt(16 - x^2) dx# using - Socratic

    WEBApr 7, 2018 · Here, I = ∫x3√16 −x2dx = ∫x2√16 −x2 ⋅ xdx. Let, x = 4sinu ⇒ x2 = 16sin2u ⇒ 2xdx = 32sinucosudu. i.e. xdx = 16sinucosudu. ⇒ I = ∫(16sin2u)√16− 16sin2u(16sinucosu)du. I = 16 × 4 × 16∫sin2u(cosu)sinucosudu. I = 1024∫sin2ucos2usinudu. = − 1024∫(1 −cos2u)cos2u(−sinu)du. = − 1024[∫(cosu)2(− sinu)du −∫

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    How do you integrate int x^3 /sqrt(16 - x^2) dx using - Socratic

    WEBMar 5, 2016 · How do you integrate #int x^3 /sqrt(16 - x^2) dx# using trigonometric substitution? Calculus Techniques of Integration Integration by Trigonometric Substitution 1 Answer

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    The equation of a parabola is (y−1)^2=16(x+3) . What is - Socratic

    WEBMay 24, 2018 · Equation of directrix is x = -7 The standard equation of parabola opening right is (y-k)^2= 4 p(x-h) , where (h,k) being vertex and directrix is x= h-p . In equation (y-1)^2= 16 (x +3) ; h= -3 , p= 4 Therefore directrix is x=-3-4 or x = -7# graph{(y-1)^2=16(x+3) [-45, 45, -22.5, 22.5]} [Ans]

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    How do you factor the expression 5x^2+16x+3? - Socratic

    WEBApr 6, 2016 · 1 Answer. Don't Memorise. Apr 6, 2016. (5x +1)(x +3) is the factorised form of the expression. Explanation: 5x2 + 16x +3. We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like ax2 + bx +c, we need to think of 2 numbers such that: N 1 ⋅ N 2 = a ⋅ c = 5 ⋅ 3 = 15.

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    16*3 - Answer | Math Problem Solver - Cymath

    WEB16*3 - Answer | Math Problem Solver - Cymath \\"Get

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    If y varies inversely as x. When y = 16, x = 3. How do you

    WEBMay 8, 2016 · Constant of variation is 48 and value of y is 6 y varies inversely as x , so y prop 1/x or y = k* 1/x or x*y=k Now x=3; y=16 :. 3*16=k or k=48 (k is constant) Hence the equation comes to x*y=48 :. when x = 8 ; y = 48/8=6[Ans]

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    How do you factor 16x^3 + 54? - Socratic

    WEBMay 22, 2015 · In general a^3+b^3= (a+b)(a^2-ab+b^2) 16x^3+54 =2((2x)^3+(3)^3) =2(2x+3)(4x^2-6x+9) How do you find the two numbers by using the factoring method, if one number is seven more than

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