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How do you factor completely #125x^3+1 - Socratic
WEB125x3 + 1 is a sum of cubes and is factorised, in general, as shown below. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣ 2 2a3 +b3 = (a +b)(a2 − ab + b2)2 2 ∣∣ ∣ −−−−−−−−−−−−−−−−−−−−−−−−−−−−−
Socratic.orgHow do you factor #125x^3 + 216#? - Socratic
WEBApr 22, 2015 · 125x3 = 5x and 216 = 63 We can use the sum of cubes to factor (125x3 + 216). (a3 + b3) = (a + b)(a2 −ab +b2) a = 5x b = 6 (5x +6)((5x)2 − (5x)(6) +62) = (5x +6
Socratic.orgHow do you factor # 125x^3+64#? - Socratic
WEBDec 14, 2015 · Help. Use the sum of cubes identity to find: 125x^3+64= (5x+4) (25x^2-20x+16) Both 125x^3 = (5x)^3 and 64 = 4^3 are perfect cubes, so this is a natural case for the sum of cubes identity: a^3+b^3= (a+b) (a^2-ab+b^2) With a=5x and b=4 we find: 125x^3+64 = (5x)^3+4^3 = (5x+4) ( (5x)^2- (5x) (4)+4^2) = (5x+4) (25x^2-20x+16)
Socratic.orgHow do you factor #125x^3 + 8y^3#? - Socratic
WEBMay 21, 2015 · 125x^3+8y^3 =(5x)^3+(2y)^3 =(5x+2y)((5x)^2-(5x)(2y)+(2y)^2) =(5x+2y)(25x^2-10xy+4y^2) using the standard factorisation: (a^3+b^3) = (a+b)(a^2 …
Socratic.orgHow do you factor #125x^3-27#? - Socratic
WEBMay 9, 2018 · 125x3 − 27 is a difference of cubes. and factors in general as. ∙ xa3 −b3 = (a −b)(a2 + ab + b2) 125x3 = (5x)3 ⇒ a = 5x. 27 = (3)3 ⇒ b = 3. ⇒ 125x3 −27 = (5x −3)((5x)2 +(5x × 3) +32) × × × × × = (5x −3)(25x2 +15x + 9) Answer link. iOS.
Socratic.orgHow do you factor #125x^3-64y^3 - Socratic
WEBOct 4, 2016 · This is the difference of two cubes, ie X^3-Y^3 = (X-Y)(X^2+XY+Y^2) (Learn This) 125x^3−64y^3=(5x)^3-(4y)^3 =(5x-4y)((5x)^2+(5x)(4y)+(4y)^2) =(5x-4y)(25x^2+20xy+16y^2)
Socratic.orgHow do you factor the expression #125x^3 + 343y^3#? - Socratic
WEBDec 10, 2015 · Factor: 125x^3 + 343y^3 Ans: (5x + 7y) (25x^2 - 35x + 49y^2) Use the algebraic identity: a^3 + b^3 = (a + b) (a^2 - ab + b^2) 125x^3 + 343y^3 = (5x + 7y) (25x^2 - 35xy + 49y^2)
Socratic.orgFactorise 125x^3 - 64y^3 - Brainly
WEBFeb 1, 2021 · Answer 6 people found it helpful minakhiengleng report flag outlined Step-by-step explanation: Explanation: 125x3−64y3= (5x)3− (4y)3 = (5x−4y) (5x)2+ (5x) (4y)+ (4y)2 = (5x−4y) (25x2+20xy+16y2)
Brainly.inHow do you factor: #y= 125x^3 - 8 - Socratic
WEBJul 26, 2016 · y=(5x-2)(25x^2+10x+4) y=125x^3-8 or y=(5x)^3-(2)^3 Since a^3-b^3-(a-b)(a^2+ab+b^2) above equation can be written as y=(5x-2)((5x)^2+(5x)(2)+(2)^2) or y=(5x-2)(25x^2
Socratic.orgFactorise 125x^3-64y^3 - Brainly
WEBFeb 9, 2019 · Solution: The given problem can be solved using standard algebra expansions. 1. The given expression 125x³ - 64y³. 2. The expression x³ -y³ can be written as. (x³ -y³) = ( x - y ) ( x² + x y + y² ). 3. Use the above formula to …
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