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How do you evaluate the integral int3^(x) dx? - Socratic
WEBMar 14, 2018 · int3^xdx=1/ln3 3^x+"c" We want to find int3^xdx. Make the natural substitution u=3^x so du=3^xln3dx. So int3^xdx=1/ln3int1du=1/ln3 u+"c"=1/ln3 3^x+"c"
Socratic.orgHow do I evaluate int3 sin(ln(x))dx? - Socratic
WEBMassimiliano. Jan 27, 2015. The answer is I = (3 4)x[sin(ln(x)) −cos(ln(x))] + c. This integral has to be done two times by parts because it is a cyclic integral. A cyclic integral is an integral of a cyclic function, like sinf (x) or cosf (x). The theorem of integration by parts says:
Socratic.orgHow do you integrate #3/((x-2)(x+1))# using partial fractions?
WEBMar 5, 2018 · Partial Fractions. 3 (x − 2)(x +1) = A x −2 + B x + 1. Multiply the whole equation by (x − 2)(x + 1) 3 = A(x + 1) +B(x − 2) expand the brackets. 3 = Ax + A+ Bx −2B. factorise. 3 = x(A+ B) +A −2B. A +B has to equal 0 because there is …
Socratic.orgHow do you integrate int 3^xdx? - Socratic
WEBMar 17, 2018 · How do you integrate #int 3^xdx#? Calculus Introduction to Integration Integrals of Exponential Functions. 1 Answer
Socratic.orgHow do you calculate the derivative of #int3(sin(t))^4 dt - Socratic
WEBJun 12, 2015 · Answer link. Use the Fundamental Theorem of Calculus, Part 1 (after rewriting) and use the chain rule. g (x) = int_ (e^x)^1 3sin^4t dt To use the fundamental theorem in one form, we must have the constant as the lower limit of integration, so we rewrite: g (x) = -int_1^ (e^x) 3sin^4t dt With u=e^x, we have: g (x) = h (u) = -int_1^ (u) …
Socratic.orgHow do you integrate #3/(x^2+4)#? - Socratic
WEBFeb 20, 2015 · I would start by factorizing 4 from the denominator: int3/ (x^2+4)dx=int3/4*1/ (1+x^2/4)dx= Now I set: x^2/4=t^2 and so x=2t giving: dx=2dt Substituting in the integral: =int3/4*1/ (1+t^2)2dt=3/2arctan (t)= Going back to x: =3/2arctan (x/2)+c.
Socratic.orgHow do you find the integral of int (1 + cos x)^2 dx? - Socratic
WEBMar 8, 2018 · Explanation: First expand the integrand using the perfect square formula. ∫(1 +cos2x)dx = ∫1 +2cosx + cos2xdx. Then use the reduction formula on cos2x to get it into an integrable form. ∫1 +2cosx + cos2xdx = ∫1 +2cosx + 1 2 + 1 2 cos2xdx = ∫ 3 2 + 2cosx + 1 2 cos2xdx. Integrate each term using the power rule or standard integrals.
Socratic.org探秘INT3指令 - 吾爱破解 - 52pojie.cn
WEBJun 3, 2020 · int3指令在调试器中的应用. 我们都知道调试器中有int3断点，而int3断点就是基于int3指令实现的。以OD为例当我们在某一汇编指令处设下断点后，调试器会把所设断点地址处的第一个字节改为0xCC（即int3指令），并把原字节保存。
52pojie.cnIntegrate intx^3/sqrt(x^2+4) using trig substitution? - Socratic
WEBOct 11, 2017 · Integrate #intx^3/sqrt(x^2+4)# using trig substitution? Calculus Techniques of Integration Integration by Trigonometric Substitution. 1 Answer
Socratic.orgHow do you integrate #int 5^x-3^xdx# from #[0,1]#? - Socratic
WEBMay 5, 2017 · Separating the integrals, we get: ∫ 1 0 5xdx −∫ 1 0 3xdx. Now use the formula ∫(ax)dx = ax ln(a). [5x ln5]1 0 − [3x ln3]1 0. 5 ln(5) − 50 ln(5) − (3 ln3 − 30 ln3) 4 ln(5) − 2 ln(3) Hopefully this helps! Answer link. The answer is =0.66 Let y=5^x Taking log on both sides lny=xln5 y=e^ (xln5) Therefore, int5^xdx=inte^ (xln5)dx=e
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